CSEC 37/G/SYLL 18 · May 2026 Edition

Every formula.
Nothing wasted.

A complete, syllabus-aligned formula book for CSEC Additional Mathematics. Each formula sits in its proper section with a short, clear note on when and why to reach for it. Built to be searched, scanned, and trusted in the final stretch.

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Kerwin Springer teaching
Kerwin Springer · The Student Hub
How to read this book
Given Printed on the CSEC formula sheet
Memorize Not on the sheet — commit it to memory
Optional Helpful but not required by the syllabus
01
Section One

Algebra, Sequences & Series

The foundation of CSEC Additional Mathematics. Master the algebraic toolkit — quadratics, polynomials, indices, logarithms, sequences — and the rest of the course follows naturally.

Quadratics

A quadratic takes the form $ax^2 + bx + c = 0$ where $a \ne 0$. You will see it everywhere: algebra, parabolas, motion problems, and inside trigonometric equations.

Quadratic FormulaMemorize
$$x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$
UseWhen the quadratic does not factorise cleanly, or when exact roots are required.
DiscriminantMemorize
$$D = b^2 - 4ac$$
Reads $D > 0$: two distinct real roots
$D = 0$: one real repeated root
$D < 0$: no real roots
Sum & Product of RootsMemorize
$$\alpha + \beta = -\dfrac{b}{a}\,,\qquad \alpha\beta = \dfrac{c}{a}$$
UseFor problems involving symmetric facts about the roots — sums, products, reciprocals.
Build a Quadratic from its RootsMemorize
$$x^2 - (\alpha + \beta)\,x + \alpha\beta = 0$$
NoteThe middle coefficient is the negative of the sum. A small sign — a frequent slip.
Completed Square FormMemorize
$$f(x) = a(x + h)^2 + k\,,\quad h = \dfrac{b}{2a}\,,\quad k = c - \dfrac{b^2}{4a}$$
Vertex$(-h,\;k)$  —  the minimum if $a>0$, the maximum if $a<0$.
AxisThe axis of symmetry is the vertical line $x = -h$.

Polynomial Division, Factor & Remainder Theorems

Two theorems that let you handle cubics and quartics without grinding through long division every time.

Factor TheoremMemorize
$$f(a) = 0 \;\;\Longrightarrow\;\; (x - a) \text{ is a factor of } f(x)$$
UseTo test whether a value is a root of a polynomial. Substitute and check for zero.
Remainder TheoremMemorize
$$f(a) = r \;\;\Longrightarrow\;\; r \text{ is the remainder of } f(x) \div (x - a)$$
NoteFor divisor $(ax + b)$ evaluate at $f\!\left(-\dfrac{b}{a}\right)$.
Long Division Layout

$\text{Dividend} = \text{Divisor} \times \text{Quotient} + \text{Remainder}$. The cycle is Divide → Multiply → Subtract → Bring down, repeated until the remainder has lower degree than the divisor.

Equations Reducible to a Quadratic

Many high-degree or surd equations collapse to a clean quadratic after one good substitution.

The SubstitutionMemorize
$$\text{Let } u = f(x) \;\;\Longrightarrow\;\; au^2 + bu + c = 0$$
TriggerYou see the shape $\big(f(x)\big)^2 + b\,f(x) + c = 0$. Solve for $u$, then back-substitute for $x$.
Example — Quartic
$$\begin{aligned}x^4 - 6x^2 + 8 &= 0 \quad\text{let } u = x^2 \\ u^2 - 6u + 8 &= 0 \\ (u-2)(u-4) &= 0 \\ x^2 = 2 \;\text{or}\; x^2 &= 4 \\ x = \pm\sqrt{2} \;\text{or}\; x &= \pm 2\end{aligned}$$
Example — Surd
$$\begin{aligned}x - 2\sqrt{x} + 1 &= 0 \quad\text{let } u = \sqrt{x} \\ u^2 - 2u + 1 &= 0 \\ (u-1)^2 &= 0 \\ u &= 1 \\ x &= 1\end{aligned}$$

Simultaneous Equations (Linear + Non-Linear)

MethodMemorize
Standard Procedure
  1. From the linear equation, express $y$ in terms of $x$ (or vice versa).
  2. Substitute into the non-linear equation.
  3. Solve the resulting quadratic.
  4. Back-substitute each $x$-value into the linear equation to recover $y$.
Discriminant of the resulting quadratic

$D > 0$ → two intersection points · $D = 0$ → tangent (one contact) · $D < 0$ → no intersection.

Inequalities

Quadratic InequalityMemorize
$$ax^2 + bx + c > 0 \quad\text{or}\quad ax^2 + bx + c < 0$$
  1. Rearrange so one side is zero.
  2. Factorise; find the roots $\alpha < \beta$.
  3. Sketch the parabola or use a sign diagram.
  4. For $a > 0$: $f(x) < 0 \Rightarrow \alpha < x < \beta$;   $f(x) > 0 \Rightarrow x < \alpha$ or $x > \beta$. For $a < 0$, the regions flip.
Rational InequalityMemorize
$$\dfrac{ax + b}{cx + d} > 0 \;\;(\text{or } \geq,\, <,\, \leq)$$
  1. Find critical values from numerator $= 0$ and denominator $= 0$.
  2. Place them on a number line.
  3. Test the sign of the fraction in each region.
  4. Select the regions that satisfy the inequality. The value that makes the denominator zero is always excluded.
Common pitfall

Never multiply both sides by $(cx + d)$ — its sign is unknown. Always use a sign diagram instead.

Set-builder notation

$\{x : 2 < x < 3\}$ reads "the set of all $x$ such that $x$ is between 2 and 3." For two separate regions: $\{x : x < -1 \text{ or } x > 4\}$.

Surds

A surd is an irrational root left in exact form. CSEC expects clean manipulation and rationalised denominators in the final answer.

MultiplicationMemorize
$$\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}$$
DivisionMemorize
$$\dfrac{\sqrt{a}}{\sqrt{b}} = \sqrt{\dfrac{a}{b}}$$
Simple RationalisationMemorize
$$\dfrac{1}{\sqrt{a}} = \dfrac{\sqrt{a}}{a}$$
Rationalising a Binomial Denominator — by the ConjugateMemorize
$$\begin{aligned} \dfrac{1}{a + \sqrt{b}} \;&=\; \dfrac{1}{a + \sqrt{b}} \times \dfrac{a - \sqrt{b}}{a - \sqrt{b}} \\[4pt] &=\; \dfrac{a - \sqrt{b}}{(a + \sqrt{b})(a - \sqrt{b})} \\[4pt] &=\; \dfrac{a - \sqrt{b}}{a^2 - b} \end{aligned}$$
KeyThe conjugate of $a + \sqrt{b}$ is $a - \sqrt{b}$. Their product is the difference of two squares: $a^2 - b$ — the surd disappears.
Mirror Image

For a denominator of $a - \sqrt{b}$, multiply by $\dfrac{a + \sqrt{b}}{a + \sqrt{b}}$. Same idea — flip the middle sign and the surd vanishes.

Indices — Laws of Exponents

Seven rules. Internalise them once; they carry you through every exponential and logarithmic equation in the syllabus.

Product
$$a^m \cdot a^n = a^{m+n}$$
Quotient
$$\dfrac{a^m}{a^n} = a^{m-n}$$
Power of a Power
$$(a^m)^n = a^{mn}$$
Identity
$$a^{\,1} = a$$
Zero Power
$$a^{\,0} = 1\,,\;\; a \ne 0$$
Negative Power
$$a^{-n} = \dfrac{1}{a^n}$$
Fractional IndicesMemorize
$$a^{1/n} = \sqrt[n]{a}\,,\qquad a^{m/n} = \sqrt[n]{a^{\,m}} = \big(\sqrt[n]{a}\big)^{m}$$
ReadDenominator is the root, numerator is the power.

Logarithms

A logarithm is an exponent in disguise. Master the bridge below, and every log law makes sense.

Log–Index BridgeMemorize
$$\log_a b = c \;\;\Longleftrightarrow\;\; a^c = b$$
BridgeConvert between log form and exponential form. Example: $\log_2 8 = 3$ because $2^3 = 8$.
Laws of Logarithms
Product
$$\log_a(PQ) = \log_a P + \log_a Q$$
Quotient
$$\log_a\!\left(\dfrac{P}{Q}\right) = \log_a P - \log_a Q$$
Power
$$\log_a(P^b) = b\log_a P$$
Log of the Base
$$\log_a a = 1$$
Log of 1
$$\log_a 1 = 0$$
Change of Base
$$\log_a b = \dfrac{\log_c b}{\log_c a}$$
Solving Exponential EquationsMemorize
$$a^x = b \;\;\Longrightarrow\;\; x = \dfrac{\log b}{\log a}$$
UseWhen both sides cannot be made the same base. Take logs of both sides.

Linear Reduction (Log-Linear Form)

Some non-linear curves straighten out when you take logs. From a straight-line graph of $\log y$ vs something, you can read off the original equation.

Power LawMemorize
$$y = ax^n \;\;\Longrightarrow\;\; \log y = n\log x + \log a$$
Plot$\log y$ on the vertical, $\log x$ on the horizontal. Gradient = $n$; intercept = $\log a$.
Exponential LawMemorize
$$y = ab^x \;\;\Longrightarrow\;\; \log y = (\log b)\,x + \log a$$
Plot$\log y$ on the vertical, $x$ on the horizontal. Gradient = $\log b$; intercept = $\log a$.
RelationshipLinear FormPlotGradientIntercept
$y = ax^n$$\log y = n\log x + \log a$$\log y$ vs $\log x$$n$$\log a$
$y = ab^x$$\log y = x\log b + \log a$$\log y$ vs $x$$\log b$$\log a$

Arithmetic Progression (A.P.)

An arithmetic progression adds the same fixed step every term. The step is the common difference $d$; the first term is $a$.

$n$th TermGiven on Exam Sheet
$$T_n = a + (n - 1)\,d$$
Sum of First $n$ TermsGiven on Exam Sheet
$$\begin{aligned} S_n \;&=\; \dfrac{n}{2}\big[\,2a + (n-1)d\,\big] \\[4pt] &=\; \dfrac{n}{2}\,(a + T_n) \end{aligned}$$
UseThe second form is faster when the last term $T_n$ is already known.
All arithmetic progressions diverge, except the trivial case $d = 0$. The terms never shrink — the sum keeps growing without bound.

Geometric Progression (G.P.)

A geometric progression multiplies by the same fixed ratio every term. The ratio is $r$; the first term is $a$.

$n$th TermGiven on Exam Sheet
$$T_n = a\,r^{\,n - 1}$$
Sum of First $n$ TermsGiven on Exam Sheet
$$\begin{aligned} S_n \;&=\; \dfrac{a\,(r^n - 1)}{r - 1}\,,\;\; r > 1 \\[6pt] S_n \;&=\; \dfrac{a\,(1 - r^n)}{1 - r}\,,\;\; 0 < r < 1 \end{aligned}$$
TipChoose whichever form keeps the numerator and denominator positive. Both give the same answer.
Sum to InfinityGiven on Exam Sheet
$$S_\infty = \dfrac{a}{1 - r}\,,\qquad -1 < r < 1$$
ConditionValid only when $|r| < 1$. Outside that range the series diverges and $S_\infty$ does not exist.
Convergence Rule

A geometric progression converges if and only if $|r| < 1$. Otherwise it diverges. Always check $r$ before using $S_\infty$.

Sigma Notation

SummationMemorize
$$\sum_{k=1}^{n} a_k = a_1 + a_2 + a_3 + \dots + a_n$$
Read$k$ is the index, starting at the lower limit. $n$ is the upper limit. $a_k$ is the general term.
Constant MultipleMemorize
$$\sum_{i=1}^{n} k\,a_i \;=\; k\sum_{i=1}^{n} a_i$$

Compound Interest & Depreciation

Both are geometric progressions in disguise. Interest grows the principal; depreciation shrinks it. Same machinery, opposite direction.

Compound InterestMemorize
$$A = P\!\left(1 + \dfrac{r}{100}\right)^{\!T}$$
Where$A$ = final amount, $P$ = principal, $r$ = rate (%) per period, $T$ = number of periods.
DepreciationMemorize
$$A = P\!\left(1 - \dfrac{r}{100}\right)^{\!T}$$
Where$A$ = depreciated value, $P$ = original value, $r$ = rate of decline (%), $T$ = number of periods.
02
Section Two

Coordinate Geometry, Vectors & Trigonometry

Where geometry meets algebra. Lines, circles, vectors, and trigonometric ratios all describe shape and direction with equations — and CSEC tests them as a connected toolkit.

Straight Lines

GradientMemorize
$$m = \dfrac{y_2 - y_1}{x_2 - x_1}$$
MeaningRate of change of $y$ with respect to $x$ between two points.
Three Equivalent Forms of a Straight Line
Slope–Intercept
$$y = mx + c$$
UseWhen you have the gradient $m$ and $y$-intercept $c$ directly.
Point–Gradient
$$y - y_1 = m(x - x_1)$$
UseWhen you have one point on the line and the gradient.
General Form
$$ax + by + c = 0$$
UseThe form most often required in the final answer.
Parallel & PerpendicularMemorize
$$\text{Parallel: } m_1 = m_2 \qquad\qquad \text{Perpendicular: } m_1 \cdot m_2 = -1$$
NotePerpendicular gradients are negative reciprocals: $m_2 = -\dfrac{1}{m_1}$.
Point of Intersection

Solve the two line equations simultaneously. The intersection point satisfies both equations at once.

Distance, Midpoint & Perpendicular Bisector

Length of a Line SegmentMemorize
$$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$
IdeaPythagoras applied between two points — the line segment is the hypotenuse of a right triangle.
MidpointMemorize
$$M = \left(\dfrac{x_1 + x_2}{2},\;\; \dfrac{y_1 + y_2}{2}\right)$$
MethodAverage the $x$-coordinates and the $y$-coordinates separately.
Perpendicular BisectorMemorize
Procedure
  1. Find the midpoint of the segment.
  2. Find the gradient of the segment.
  3. Take the perpendicular gradient $\;m_\perp = -\dfrac{1}{m}$.
  4. Apply point–gradient form using the midpoint and $m_\perp$.

Circles

CSEC gives circles in two forms. Standard form shows the centre and radius directly; general form is the form you'll most often have to convert from.

Standard FormGiven on Exam Sheet
$$(x - a)^2 + (y - b)^2 = r^2$$
Centre$(a,\;b)$ — read straight from the equation.
Radius$r$ — the square root of the right-hand side.
General FormGiven on Exam Sheet
$$x^2 + y^2 + 2fx + 2gy + c = 0$$
Centre$(-f,\;-g)$
Radius$r = \sqrt{f^2 + g^2 - c}$
Conversion Shortcut

Compare coefficients directly: $2f$ is the coefficient of $x$, $2g$ is the coefficient of $y$, $c$ is the constant. Then centre and radius come straight from the formulas above — no completing the square required.

Circle from Diameter EndpointsMemorize
  1. Centre = midpoint of the two endpoints.
  2. Radius = half the distance between them.
  3. Substitute into the standard form $(x - a)^2 + (y - b)^2 = r^2$.

Tangent & Normal to a Circle

A radius drawn to a point on the circle is perpendicular to the tangent at that point. That single fact powers every question on this topic.

Tangent at a PointMemorize
$$m_{\text{tangent}} = -\dfrac{1}{m_{\text{radius}}}$$
  1. Find the centre of the circle.
  2. Compute the gradient of the radius to the given point.
  3. Tangent gradient is the negative reciprocal.
  4. Apply point–gradient form.
Normal at a PointMemorize
$$m_{\text{normal}} = m_{\text{radius}}$$
Key insightThe normal to a circle is the radius extended. It passes through the centre. Use point–gradient form with the point on the circle.

Line–Circle Intersection

MethodMemorize
  1. From the linear equation, express $y$ in terms of $x$.
  2. Substitute into the circle equation.
  3. Solve the resulting quadratic.
  4. Back-substitute to find the $y$-coordinates.
Reading the Discriminant

$D > 0$ → two intersection points · $D = 0$ → tangent (one point of contact) · $D < 0$ → the line misses the circle.

Vectors

A vector carries both magnitude and direction. CSEC works exclusively in two dimensions and accepts either column form or $\mathbf{i}, \mathbf{j}$ form.

Two Equivalent NotationsMemorize
$$\mathbf{v} = \begin{pmatrix} x \\ y \end{pmatrix} = x\mathbf{i} + y\mathbf{j}$$
Where$\mathbf{i} = \begin{pmatrix}1\\0\end{pmatrix}$ along the $x$-axis, $\mathbf{j} = \begin{pmatrix}0\\1\end{pmatrix}$ along the $y$-axis.
Magnitude (Modulus)Given on Exam Sheet
$$|\mathbf{v}| = \sqrt{x^2 + y^2}$$
IdeaPythagoras on the components. This is the vector's length.
Unit VectorGiven on Exam Sheet
$$\hat{\mathbf{v}} = \dfrac{\mathbf{v}}{|\mathbf{v}|}$$
MeaningA vector of length 1 in the same direction as $\mathbf{v}$.
Equality of VectorsMemorize
$$\mathbf{a} = \mathbf{b} \;\;\Longleftrightarrow\;\; a_1 = b_1 \;\text{and}\; a_2 = b_2$$
UseEach component must match — gives you a pair of simultaneous equations.
Operations on VectorsMemorize
$$\mathbf{a} + \mathbf{b} = \begin{pmatrix} a_1 + b_1 \\ a_2 + b_2 \end{pmatrix}\;,\qquad \mathbf{a} - \mathbf{b} = \begin{pmatrix} a_1 - b_1 \\ a_2 - b_2 \end{pmatrix}\;,\qquad k\mathbf{a} = \begin{pmatrix} k a_1 \\ k a_2 \end{pmatrix}$$
RuleOperate on each component independently.
Displacement VectorMemorize
$$\overrightarrow{AB} = \mathbf{b} - \mathbf{a}$$
Read as"End minus start." The displacement from $A$ to $B$ when $\mathbf{a}$, $\mathbf{b}$ are the position vectors.

Dot Product & the Angle Between Vectors

Dot ProductGiven on Exam Sheet
$$\begin{aligned} \mathbf{a} \cdot \mathbf{b} \;&=\; a_1 b_1 + a_2 b_2 \\[4pt] &=\; |\mathbf{a}|\,|\mathbf{b}|\,\cos\theta \end{aligned}$$
Two facesCompute from components; or from magnitudes and the included angle. Setting them equal is how you solve for $\theta$.
Angle Between Two VectorsGiven on Exam Sheet
$$\cos\theta = \dfrac{\mathbf{a} \cdot \mathbf{b}}{|\mathbf{a}|\,|\mathbf{b}|}$$
RangeAlways returns $0 \le \theta \le 180°$. If $\cos\theta$ is negative, $\theta$ is obtuse.
Parallel & Perpendicular VectorsMemorize
$$\text{Perpendicular: } \mathbf{a} \cdot \mathbf{b} = 0 \qquad\qquad \text{Parallel: } \mathbf{a} = k\mathbf{b}$$
WhyPerpendicular: $\cos 90° = 0$. Parallel: one vector is a scalar multiple of the other.

Radians, Arc Length & Sector Area

CSEC trigonometry works in radians by default. Always confirm the units before plugging in.

Degrees ↔ RadiansMemorize
$$\pi \text{ rad} = 180°\,,\quad 1\text{ rad} = \dfrac{180°}{\pi}\,,\quad 1° = \dfrac{\pi}{180}\text{ rad}$$
ConversionsMultiply degrees by $\dfrac{\pi}{180}$ to get radians. Multiply radians by $\dfrac{180}{\pi}$ to get degrees.
Arc LengthMemorize
$$s = r\theta \quad\text{or}\quad \ell = r\theta$$
Required$\theta$ in radians. The arc is the fraction $\dfrac{\theta}{2\pi}$ of the full circumference.
Sector AreaMemorize
$$A = \tfrac{1}{2}\, r^2 \theta$$
Required$\theta$ in radians. The sector is the fraction $\dfrac{\theta}{2\pi}$ of the full area $\pi r^2$.
Segment AreaMemorize
$$A_{\text{segment}} = \tfrac{1}{2}\, r^2 (\theta - \sin\theta)$$
IdeaThe region between a chord and its arc. Sector area minus the triangle inside it.

Exact Values & the CAST Diagram

Exact Values
Angle
0(0°)
$\dfrac{\pi}{6}$(30°)
$\dfrac{\pi}{4}$(45°)
$\dfrac{\pi}{3}$(60°)
$\dfrac{\pi}{2}$(90°)
$\sin\theta$
$0$
$\dfrac{1}{2}$
$\dfrac{\sqrt{2}}{2}$
$\dfrac{\sqrt{3}}{2}$
$1$
$\cos\theta$
$1$
$\dfrac{\sqrt{3}}{2}$
$\dfrac{\sqrt{2}}{2}$
$\dfrac{1}{2}$
$0$
$\tan\theta$
$0$
$\dfrac{1}{\sqrt{3}}$
$1$
$\sqrt{3}$
undefined
CAST — Signs by Quadrant
Quadrant 2 · 90°–180°
S
Sine positive
$\sin\theta > 0$
$\cos\theta < 0$
$\tan\theta < 0$
Quadrant 1 · 0°–90°
A
All positive
$\sin\theta > 0$
$\cos\theta > 0$
$\tan\theta > 0$
Quadrant 3 · 180°–270°
T
Tan positive
$\sin\theta < 0$
$\cos\theta < 0$
$\tan\theta > 0$
Quadrant 4 · 270°–360°
C
Cosine positive
$\sin\theta < 0$
$\cos\theta > 0$
$\tan\theta < 0$
Related Angles

Once you find the principal (acute) angle, use CAST to locate the other solutions in the range:
Quadrant 2: $180° - \theta$  ·  Quadrant 3: $180° + \theta$  ·  Quadrant 4: $360° - \theta$.

Pythagorean & Quotient Identities

Pythagorean IdentityMemorize
$$\sin^2\theta + \cos^2\theta \;\equiv\; 1$$
Rearrangements$\sin^2\theta = 1 - \cos^2\theta$  and  $\cos^2\theta = 1 - \sin^2\theta$.
Quotient IdentityMemorize
$$\tan\theta \;\equiv\; \dfrac{\sin\theta}{\cos\theta}$$
UseTo eliminate $\tan\theta$ from an equation, or to simplify expressions mixing sin, cos, tan.

Compound & Double Angle Formulae

Compound Angle — SineGiven on Exam Sheet
$$\sin(A \pm B) \;=\; \sin A \cos B \;\pm\; \cos A \sin B$$
Sign ruleThe signs match — straightforward.
Compound Angle — CosineGiven on Exam Sheet
$$\cos(A \pm B) \;=\; \cos A \cos B \;\mp\; \sin A \sin B$$
Sign ruleThe signs are opposite. Most common slip in the entire topic.
Compound Angle — TangentMemorize
$$\tan(A \pm B) \;=\; \dfrac{\tan A \pm \tan B}{1 \mp \tan A \tan B}$$
Sign ruleTop signs match, bottom signs flip.
Double-Angle Formulae (set $B = A$)
$\sin 2A$Memorize
$$\sin 2A \;=\; 2\sin A \cos A$$
$\tan 2A$Memorize
$$\tan 2A \;=\; \dfrac{2\tan A}{1 - \tan^2 A}$$
$\cos 2A$ — Three Equivalent Forms
When equation has both
$\cos 2A = \cos^2 A - \sin^2 A$
Use this form for identity proofs or when a mix of $\sin^2$ and $\cos^2$ is present.
When other $\sin^2$ terms appear
$\cos 2A = 1 - 2\sin^2 A$
Substitute to collapse the equation into a quadratic in $\sin A$.
When other $\cos^2$ terms appear
$\cos 2A = 2\cos^2 A - 1$
Substitute to collapse the equation into a quadratic in $\cos A$.

Triangle Area & Trig Graphs

Area of a TriangleMemorize
$$\text{Area} = \tfrac{1}{2}\, ab \sin C$$
UseWhen two sides $a, b$ and the included angle $C$ are known.
Graphs of $\sin kx$, $\cos kx$, $\tan kx$
FunctionAmplitudePeriodKey Feature
$\sin kx$$1$$\dfrac{2\pi}{k}$Starts at 0, rises first
$\cos kx$$1$$\dfrac{2\pi}{k}$Starts at 1 (the maximum)
$\tan kx$undefined$\dfrac{\pi}{k}$Vertical asymptotes at odd multiples of $\dfrac{\pi}{2k}$
The role of $k$

$k$ compresses the graph horizontally — doubling $k$ halves the period and doubles the number of cycles in $[0, 2\pi]$.

03
Section Three

Introductory Calculus

Calculus is the mathematics of change. Differentiation gives the gradient at a point; integration reverses that and recovers the original function — or the area beneath the curve.

Differentiation — The Basic Rules

Power Rule (Standard)Memorize
$$\dfrac{d}{dx}\big(x^n\big) = n\,x^{\,n-1}$$
UseFor any power of $x$. This is the rule you reach for every single day.
Power Rule with Linear InnerGiven on Exam Sheet
$$\dfrac{d}{dx}\big(ax + b\big)^n = a\,n\,(ax + b)^{n - 1}$$
UseFor brackets raised to a power. The factor of $a$ comes from the chain rule on the inside.
Constant
$$\dfrac{d}{dx}(c) = 0$$
Sum & Difference
$$\dfrac{d}{dx}\!\big[f \pm g\big] = f' \pm g'$$
Constant Multiple
$$\dfrac{d}{dx}\!\big[k f(x)\big] = k f'(x)$$

Trig Derivatives

SineGiven on Exam Sheet
$$\dfrac{d}{dx}\sin ax = a \cos ax$$
NoteFor just $\sin x$, the derivative is $\cos x$.
CosineGiven on Exam Sheet
$$\dfrac{d}{dx}\cos ax = -a \sin ax$$
NoteFor just $\cos x$, the derivative is $-\sin x$.
CSEC Scope

Differentiation of $\tan x$ is not part of the CSEC Add Math syllabus. Only polynomials, sine, and cosine are required.

Chain, Product & Quotient Rules

Chain RuleMemorize
$$\dfrac{dy}{dx} \;=\; \dfrac{dy}{du} \times \dfrac{du}{dx}$$
UseFor a function of a function. Let $u$ be the inner expression, differentiate the outer in terms of $u$, then multiply by the derivative of $u$ with respect to $x$.
Chain Rule — Linear Inner ShortcutMemorize
$$\dfrac{d}{dx}\big[f(ax + b)\big] \;=\; a \cdot f'(ax + b)$$
Example$\dfrac{d}{dx}(5x + 1)^4 = 4(5x + 1)^3 \cdot 5 = 20(5x + 1)^3$.
Product RuleMemorize
$$\dfrac{d}{dx}(uv) \;=\; u\dfrac{dv}{dx} + v\dfrac{du}{dx}$$
UseFor a product of two functions. The derivative of a product is not the product of derivatives.
Quotient RuleMemorize
$$\dfrac{d}{dx}\!\left(\dfrac{u}{v}\right) \;=\; \dfrac{v\,\dfrac{du}{dx} - u\,\dfrac{dv}{dx}}{v^2}$$
UseFor a quotient of two functions. Mind the order in the numerator — the minus sign matters.

The Second Derivative

Second DerivativeMemorize
$$\dfrac{d^2 y}{dx^2} \;=\; f''(x) \;=\; \dfrac{d}{dx}\!\left(\dfrac{dy}{dx}\right)$$
MeaningThe rate of change of the gradient itself — tells you how the curve is bending.

Stationary Points & Their Nature

A stationary point is where the gradient is momentarily zero. From there it is either a maximum, a minimum, or a point of inflexion (excluded from CSEC).

Stationary PointMemorize
$$\dfrac{dy}{dx} = 0$$
ProcessDifferentiate, set $f'(x) = 0$, solve for $x$, then back-substitute to find the $y$-coordinate.
Method 1 — Second Derivative Test
Second Derivative TestMemorize
$$f''(x) > 0 \Rightarrow \text{min},\quad f''(x) < 0 \Rightarrow \text{max}$$
InconclusiveIf $f''(x) = 0$, fall back to Method 2.
Minimum f ′′(x) > 0 Maximum f ′′(x) < 0
A concave-up curve has $f''(x) > 0$ at its minimum. A concave-down curve has $f''(x) < 0$ at its maximum.
Method 2 — First Derivative Sign-Change Test
Procedure

Pick an $x$ slightly less than the stationary point and slightly more. Check the sign of $f'(x)$ in each.

Sign goes $-$ to $+$ → minimum  ·  Sign goes $+$ to $-$ → maximum  ·  No change → point of inflexion (not in CSEC).

Tangent & Normal to a Curve

Tangent at $x = a$Memorize
$$m_{\text{tangent}} = f'(a)$$
ThenUse point–gradient form $\;y - y_1 = m(x - x_1)$ with the point $(a,\,f(a))$.
Normal at $x = a$Memorize
$$m_{\text{normal}} = -\dfrac{1}{f'(a)}$$
WhyPerpendicular to the tangent — negative reciprocal gradient. Same point on the curve.

Differentiation from First Principles

Definition of the DerivativeMemorize
$$\dfrac{dy}{dx} \;=\; \lim_{h \to 0}\, \dfrac{f(x + h) - f(x)}{h}$$
IdeaThe limit of the gradient of a secant line as the two points squeeze together. The coordinate-geometry gradient taken at infinitesimally close points.

Related Rates of Change

Chain Rule for Related RatesMemorize
$$\dfrac{dy}{dx} \;=\; \dfrac{dy}{du} \times \dfrac{du}{dx}$$
ExampleFor a circle of radius $r$, the area $A = \pi r^2$ changes with time via $\dfrac{dA}{dt} = \dfrac{dA}{dr} \cdot \dfrac{dr}{dt} = 2\pi r \cdot \dfrac{dr}{dt}$.

Integration — The Basic Rules

Integration reverses differentiation. It also accumulates change — giving the area under a curve.

Power RuleMemorize
$$\int x^n\, dx \;=\; \dfrac{x^{\,n+1}}{n + 1} + c\,,\qquad n \ne -1$$
Read"Raise the power by one; divide by the new power." Always add the constant of integration $c$ for an indefinite integral.
$(ax + b)^n$ FormMemorize
$$\int (ax + b)^n\, dx \;=\; \dfrac{(ax + b)^{\,n+1}}{a\,(n + 1)} + c\,,\qquad n \ne -1$$
UsePower rule with an extra divide-by-the-inside-coefficient.
Constant
$$\int k\, dx = kx + c$$
Sum & Difference
$$\int(f \pm g)\, dx = \int\! f\, dx \pm \int\! g\, dx$$
Constant Multiple
$$\int k\,f(x)\, dx = k\!\int f(x)\, dx$$

Trig Integrals

Integrating $\sin ax$Memorize
$$\int \sin ax\, dx = -\dfrac{1}{a}\cos ax + c$$
Integrating $\cos ax$Memorize
$$\int \cos ax\, dx = \dfrac{1}{a}\sin ax + c$$

Definite Integrals

Definite IntegralMemorize
$$\int_a^b f(x)\, dx \;=\; \Big[F(x)\Big]_a^b \;=\; F(b) - F(a)$$
Note$F(x)$ is any antiderivative. The constant of integration $c$ cancels when you subtract.

Area & Volume by Integration

Area Under a CurveMemorize
$$A = \int_a^b f(x)\, dx$$
ScopeCSEC restricts this to regions in the first quadrant, bounded by the curve, the $x$-axis, and the lines $x = a$ and $x = b$.
a b Area y = f(x)
Volume of Revolution about the $x$-axisMemorize
$$V = \pi \int_a^b \big[f(x)\big]^2 dx$$
IdeaRotate the region under $y = f(x)$ a full turn about the $x$-axis. Each thin strip becomes a disc of area $\pi y^2$. CSEC restricts this to polynomials up to degree 2.

Equation of a Curve from its Gradient

Reverse the DifferentiationMemorize
$$y \;=\; \int \dfrac{dy}{dx}\, dx \;+\; c$$
UseWhen given the gradient function and a point on the curve. Integrate, then substitute the point to find $c$.

Kinematics

Kinematics is calculus applied to motion. Differentiate to move forward through the chain; integrate to move backward.

Displacement
$s(t)$
position relative to a fixed origin
↑ integrate  (add constant) differentiate ↓
Velocity
$v = \dfrac{ds}{dt}$
rate of change of displacement
↑ integrate  (add constant) differentiate ↓
Acceleration
$a = \dfrac{dv}{dt} = \dfrac{d^2 s}{dt^2}$
rate of change of velocity
Forward — DifferentiateGiven on Exam Sheet
$$v = \dfrac{dx}{dt} = \dot{x}\,,\qquad a = \dfrac{d^2 x}{dt^2} = \dfrac{dv}{dt} = \ddot{x}$$
Reverse — IntegrateGiven on Exam Sheet
$$s = \int v\, dt\,,\qquad v = \int a\, dt$$
Displacement vs Total Distance

$\displaystyle s = \int_a^b v(t)\, dt$ can be negative when the particle moves backwards. For total distance use $|v(t)|$: $\displaystyle \text{Distance} = \int_a^b |v(t)|\, dt$. Find when $v(t) = 0$, split the integral there, and add the absolute values.

SUVAT — Equations of Motion Optional

SUVAT applies only when acceleration is constant. CSEC Add Math does not require these — every kinematics question can be solved using the calculus approach above. SUVAT can occasionally provide a faster route, so it is worth knowing.

Final Velocity
$$v = u + at$$
Displacement
$$s = ut + \tfrac{1}{2} at^2$$
Without Time
$$v^2 = u^2 + 2as$$
04
Section Four

Probability & Statistics

Statistics is half computation, half careful reading of data. Probability is half logic, half clean diagram work. Lock the formulas in, then practise reading questions slowly — that is where the marks slip.

Types of Data

TypeMeaningExample
QualitativeNon-numerical categoriesColours, gender, blood type
Quantitative — DiscreteCountable numbersNumber of students, goals scored
Quantitative — ContinuousAny value in a rangeHeight, weight, time, temperature

Mean, Median & Mode

Mean — UngroupedGiven on Exam Sheet
$$\bar{x} \;=\; \dfrac{\displaystyle\sum_{i=1}^{n} x_i}{n}$$
ReadSum of all the values, divided by how many there are.
Mean — GroupedGiven on Exam Sheet
$$\bar{x} \;=\; \dfrac{\displaystyle\sum_{i=1}^{n} f_i\, x_i}{\displaystyle\sum_{i=1}^{n} f_i}$$
NoteUse class midpoints for $x_i$. Each midpoint is weighted by its frequency.
Median & ModeMemorize
$$\text{Median position:} \;\; \tfrac{1}{2}(n + 1)^{\text{th}} \text{ term (raw)} \quad\text{or}\quad \tfrac{1}{2}n^{\text{th}} \text{ term (grouped / large data)}$$
ModeThe value (or class) that occurs most frequently.

Quartiles & Interquartile Range

Quartiles — Raw DataMemorize
$$\begin{aligned} Q_1 &= \tfrac{1}{4}(n + 1)^{\text{th}} \text{ term} \\ Q_2 &= \tfrac{1}{2}(n + 1)^{\text{th}} \text{ term} \\ Q_3 &= \tfrac{3}{4}(n + 1)^{\text{th}} \text{ term} \end{aligned}$$
UseFor small, ordered lists of individual values.
Quartiles — Grouped / Large DataMemorize
$$\begin{aligned} Q_1 &= \tfrac{1}{4}\,n^{\text{th}} \text{ term} \\ Q_2 &= \tfrac{1}{2}\,n^{\text{th}} \text{ term} \\ Q_3 &= \tfrac{3}{4}\,n^{\text{th}} \text{ term} \end{aligned}$$
UseFor grouped frequency tables and large datasets — typically read from a cumulative frequency curve.
Interquartile RangeMemorize
$$\text{IQR} \;=\; Q_3 - Q_1$$
MeaningThe spread of the middle 50% of the data. Robust to extreme values.
Semi-IQRMemorize
$$\text{Semi-IQR} \;=\; \dfrac{Q_3 - Q_1}{2}$$
NoteHalf the interquartile range.

Variance & Standard Deviation

Variance — UngroupedGiven on Exam Sheet
$$\begin{aligned} S^2 \;&=\; \dfrac{\displaystyle\sum_{i=1}^{n} (x_i - \bar{x})^2}{n} \\[6pt] &=\; \dfrac{\displaystyle\sum_{i=1}^{n} x_i^{\,2}}{n} \;-\; (\bar{x})^2 \end{aligned}$$
TipThe second form is the calculator-friendly shortcut.
Variance — GroupedGiven on Exam Sheet
$$S^2 \;=\; \dfrac{\displaystyle\sum_{i=1}^{n} f_i\, x_i^{\,2}}{\displaystyle\sum_{i=1}^{n} f_i} \;-\; (\bar{x})^2$$
NoteUse class midpoints for $x_i$, weighted by frequency.
Standard DeviationMemorize
$$S \;=\; \sqrt{S^2}$$
NoteSame units as the original data — easier to interpret than variance. Always find variance first.

Box-and-Whisker Plots & Stem-and-Leaf

A box-and-whisker plot displays the five-number summary: Minimum, $Q_1$, Median ($Q_2$), $Q_3$, Maximum. The box spans $Q_1$ to $Q_3$; the line inside marks the median; the whiskers extend to the extremes.

Positive Skew median left of centre Symmetric median centred Negative Skew median right of centre
Skewness from the box plot: the position of the median line inside the box tells you which way the data is pulled.
Stem-and-Leaf

Split each value into a stem (leading digits) and a leaf (final digit). Preserves the original values, so median, quartiles, and mode can all be read directly. Always include a key such as "$1\,|\,2$ means $12$."

Probability Foundations

An experiment produces an outcome. The sample space $S$ is the set of all possible outcomes. An event $A$ is a subset of the sample space.

Classical ProbabilityMemorize
$$P(A) \;=\; \dfrac{\text{number of outcomes in } A}{\text{total number of outcomes in } S}$$
ConditionAll outcomes must be equally likely — coins, fair dice, balls drawn at random.
Range
$$0 \le P(A) \le 1$$
Sample Space
$$\sum_{\text{outcomes}} P = 1$$
Complement
$$P(A') = 1 - P(A)$$

Addition Rule & Mutually Exclusive Events

Addition RuleGiven on Exam Sheet
$$P(A \cup B) \;=\; P(A) + P(B) - P(A \cap B)$$
Why subtract?Adding $P(A)$ and $P(B)$ counts the overlap $P(A \cap B)$ twice. Subtracting it once removes the duplicate.
Mutually Exclusive EventsMemorize
$$P(A \cap B) = 0 \;\;\Longrightarrow\;\; P(A \cup B) = P(A) + P(B)$$
MeaningThe events cannot both happen — rolling a 2 and rolling a 5 on the same die. No overlap, no subtraction.

Conditional Probability

Conditional ProbabilityMemorize
$$P(A | B) \;=\; \dfrac{P(A \cap B)}{P(B)}$$
Read"The probability of $A$, given that $B$ has occurred." Knowing $B$ restricts the sample space to $B$, and we recompute within that restricted space.

Independent Events

Independence ConditionMemorize
$$P(A \cap B) = P(A) \times P(B) \qquad\text{or equivalently}\qquad P(A | B) = P(A)$$
MeaningOne event does not affect the other — like tossing two separate coins. Either condition can be used to prove independence.
Common Confusion

Mutually exclusive is not the same as independent. If two events are mutually exclusive (and both have non-zero probability), they cannot be independent — knowing one happened tells you the other did not.

Tree Diagrams, Venn Diagrams & Possibility Spaces

Tree Diagrams

Multiply along branches for "and" — joint probability of $A$ then $B$.

Add across branches for "or" — total probability of an outcome reached by more than one path.

CSEC limits trees to two initial branches.

Venn Diagrams (Two Sets)

$A \cap B$: inside both circles
$A \cap B'$: inside $A$ only
$A' \cap B$: inside $B$ only
$(A \cup B)'$: outside both

Always fill in $P(A \cap B)$ first, then work outward.

Possibility Spaces

A grid of all outcome pairs from two experiments — e.g. rolling two dice gives a 6 × 6 grid.

$$P(\text{event}) = \dfrac{\text{favourable squares}}{\text{total squares}}$$

Quick Reference
LawFormula
Complement$P(A') = 1 - P(A)$
Addition (general)$P(A \cup B) = P(A) + P(B) - P(A \cap B)$
Mutually exclusive$P(A \cup B) = P(A) + P(B)$
Conditional$P(A | B) = \dfrac{P(A \cap B)}{P(B)}$
Independent$P(A \cap B) = P(A) \times P(B)$
Every CSEC Additional Mathematics formula, arranged in syllabus order, presented the way I teach it. Search anything, jump anywhere, share with your class — this book is yours. — Kerwin